Well, for the longsword, you have a 10% chance to threaten critical. If you do, on the first attack you have a 55% chance of actually landing the critical, a 30% chance of actually landing a critical on the second, 5% on the third, and 0% on the fourth.
So if you break the attacks down...
First attack- 55% chance for a hit
- Within that 55% chance for a hit you have a 5.5% chance for a crit. Thus a 49.5% hit and 5.5% crit
- With a x2 multiplier, you get 49.5% + 11% = 60.5% damage of a hit
Second attack is 30% hit with a 3% crit, so 27% + 6% = 33% damage of a hit
Third attack is 5% hit with a 5% crit, so 4.75% + 0.5% = 5.25%
Fourth attack is 5% hit, no chance of a crit, so 5%.
60.5% + 33% + 5.25% + 5% = 103.75% hits per round
8.5 damage * 1.0375 = 8.81875 (round it to 8.82).
Edit: Curious to see where the difference between my number and MrZork's comes from.
Edit 2:
MrZork wrote...
For example, if the same attacker above were using a keen scimitar against an AC 35 opponent, the bh[1+c(m-1)] formula (above) gives DPR of 4.4, whereas true DPR is 3.6. Still not a huge difference, but whether it's worth working out depends on what you're doing with the information.
So...
0.3/0.05/0.05/0.5 with the scimitar
Default formula would give 0.45 * 7.5 * 1.3 = 4.3875 (round to 4.4)
Actual breakdown gives...
30% chance to hit, 30% of the hits will be crits, so 21% + 18% = 39%
5% chance to hit, 5% chance to crit, so 4.75% + 0.25% = 5.25%
5% chance to hit, 0% chance to crit = 5%
5% chance to hit, 0% chance to crit = 5%
So 39% + 5.25% + 5% + 5% = 54.25%
7.5 * 0.5425 = 4.06875 (round to 4.1)
Modifié par MagicalMaster, 26 août 2012 - 04:24 .