Check for partial tag name?

[Legacy_Buddywarrior]

               I need to remove from inventory any item (equiped or not) that has the beggining tag line of 'summoned_'

summoned_water
summoned_bandages

How can I check for partial tag name?
               
               

               
            

[Legacy_Lightfoot8]

               object oItem = GetFirstItemInInventory (oPC);
while (GetIsObjectValid (oItem) )
      {
        if (GetStringLeft(GetTag (oItem),9) == "summoned_") DestroyObject  (oItem);            
        oItem = GetNextItemInInventory(oPC);
       }
               
               

               
            

[Legacy_meaglyn]

               Try something like

if (GetStringLeft(sTag, 9) == "summoned_") {
         /remove it
}

where sTag is the tag of an item.
               
               

               
            

[Legacy_GhostOfGod]

               A simple example:

void main()
{
    object oItem; //however defined
    string sTag = GetTag(oItem);
    string sCheck = GetStringLeft(sTag, ;

    if (sCheck == "summoned")
    {
        //destroy object
    }
}


Edit: Haha. looks like a few decided to answer at the same time. I'm a little late.
               
               

               

                     Modifié par GhostOfGod, 27 mars 2012 - 06:57 .
                     
                  

            

[Legacy_Buddywarrior]

               Thanks a ton guys. So glad that you guys still keep these forums alive. Still the best game to date imo.
               
               

               

                     Modifié par Buddywarrior, 28 mars 2012 - 01:29 .
                     
                  

            

[Legacy__Guile]

               

GhostOfGod wrote...

A simple example:

void main()
{
    object oItem; //however defined
    string sTag = GetTag(oItem);
    string sCheck = GetStringLeft(sTag, ;

    if (sCheck == "summoned")
    {
        //destroy object
    }
}


Edit: Haha. looks like a few decided to answer at the same time. I'm a little late.

Yes but your code is a complete script, which means you aren't lazy. '>
               
               

               
            

[Legacy_meaglyn]

               Heh, name calling already, you're just upset you didn't get to put your answer in at the same time as the rest of us '>

And FWIW, GhostOfGod's script isn't really "complete" either, now is it?